1-7-1 求幂级数展开的部分和

``````#include<stdio.h>
#include<math.h>
int main()
{
double x = 0;
scanf("%lf",&x);
double add = 1.0,sum = 1.0;
int i = 1;
for(i = 1;;i++)
{
break;
}
printf("%.4lf",sum);
return 0;
}
``````

1-7-2 查询水果价格

``````#include<stdio.h>
{
printf("[1] applen[2] pearn[3] orangen[4] grapen[0] exitn");
}

int main()
{
int c = 0, n;
while(++c<6)
{
scanf("%d",&n);
if(n == 0)
break;

switch(n)
{
case 1:printf("price = 3.00n");
break;
case 2:printf("price = 2.50n");
break;
case 3:printf("price = 4.10n");
break;
case 4:printf("price = 10.20n");
break;
default:printf("price = 0.00n");
break;
}
}
return 0;
}
``````

1-7-3 猜数字游戏

``````#include<stdio.h>
int main()
{
int gs = 0;
{

for(int i = 0;i<N;i++)
{
scanf("%d", &gs);
if (gs <= 0)
{
printf("Game Over");
return 0;
}
printf("Too smalln");
printf("Too bign");
{
printf("Bingo!n");
return 0;
}
else if(gs == rad1&&(i == 1||i==2))
{
printf("Lucky You!n");
return 0;
}
{
printf("Good Guess!n");
return 0;
}
}

printf("Game Overn");
return 0;
}

}
``````

1-7-4 特殊a串数列求和

``````#include<stdio.h>
int main()
{
int a,n;
scanf("%d%d",&a,&n);
int s = 0,sum = 0;
for(int i = 1;i<=n;i++)
{
s = s*10+a;
sum += s;
}
printf("s = %d",sum);
}
``````

1-7-5 成绩统计分析表

``````#include<stdio.h>

void Print_s(double i)//把打印*封装成一个函数，方便
{
int n = (int)floor(i+0.5);//四舍五入
for(int j = 0;j<n;j++)
printf("*");
}

int main()
{
int n;
scanf("%d", &n);
double arr[1000] = { 0.0 };
double sum = 0.0,max = 0.0,min = 1000.0,avg;
int a=0,b=0,c=0,d=0,e=0;
for (int i = 0; i < n; i++)
{
scanf("%lf", &arr[i]);
sum += arr[i];
if(arr[i]>max)
max = arr[i];
if(arr[i]<min)
min = arr[i];

if(arr[i]>=90&&arr[i]<=100)
a++;
else if(arr[i]>=80&&arr[i]<90)
b++;
else if(arr[i]>=70&&arr[i]<80)
c++;
else if(arr[i]>=60&&arr[i]<70)
d++;
else if(arr[i]>=0&&arr[i]<60)
e++;
}
for (int i = 0; i < n; i++)
{
printf("%03d:%6.1lf ", i+1, arr[i]);
Print_s(arr[i]);
printf("n");
}
avg = sum / n;
printf("nMax: %5.1lf ",max);
Print_s(max);
printf("nMin: %5.1lf ",min);
Print_s(min);
printf("nAvg: %5.1lf ",avg);
Print_s(avg);
printf("n");

double A = 100.0*a/n,B=100.0*b/n,C = 100.0*c/n,D = 100.0*d/n,E = 100.0*e/n;

//printf里打印一个百分号“%”要写两个：%%
printf("nA:%6.1lf%%",A);
printf(" ");
Print_s(A);
printf("nB:%6.1lf%%",B);
printf(" ");
Print_s(B);
printf("nC:%6.1lf%%",C);
printf(" ");
Print_s(C);
printf("nD:%6.1lf%%",D);
printf(" ");
Print_s(D);
printf("nE:%6.1lf%%",E);
printf(" ");
Print_s(E);
return 0;
}
``````

1-7-6 换硬币

``````#include<stdio.h>
int main()
{
int x = 0;
scanf("%d", &x);
int f5 = 0, f2 = 0, f1 = 0;
int count = 0;
for (int i = x/5;; i--)
{
f5 = i;
for (int j = (x-5*f5)/2;; j--)
{
f2 = j;
f1 = x - 5 * f5 - 2 * f2;
if (f2 == 0)
{
break;
}
if (f1 <= 0)
{
continue;
}
printf("fen5:%d, fen2:%d, fen1:%d, total:%dn", f5, f2, f1, f1 + f2 + f5);
count++;
}
if ((f5 == 1))
{
printf("count = %dn", count);
break;
}
}
return 0;
}
``````

1-7-7 验证“哥德巴赫猜想”

``````#include<stdio.h>
#include<math.h>
int Prime(long long i)
{
int c = 0;
for(long long int j = 2;j<=sqrt(i);j++)
{
if(i%j==0)
return 0;
}
return 1;
}

int main()
{
long long int n;
scanf("%lld",&n);
for(long long int i = 2;i<n;i++)
{
if(Prime(i)&&Prime(n-i))
{
printf("%lld = %lld + %lld",n,i,n-i);
break;
}
else
continue;
}
return 0;
}
``````

THE END

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